Optimal. Leaf size=322 \[ -\frac{x^{7/2} (11 b B-3 A c)}{16 b c^2 \left (b+c x^2\right )}+\frac{7 x^{3/2} (11 b B-3 A c)}{48 b c^3}-\frac{7 (11 b B-3 A c) \log \left (-\sqrt{2} \sqrt [4]{b} \sqrt [4]{c} \sqrt{x}+\sqrt{b}+\sqrt{c} x\right )}{64 \sqrt{2} \sqrt [4]{b} c^{15/4}}+\frac{7 (11 b B-3 A c) \log \left (\sqrt{2} \sqrt [4]{b} \sqrt [4]{c} \sqrt{x}+\sqrt{b}+\sqrt{c} x\right )}{64 \sqrt{2} \sqrt [4]{b} c^{15/4}}+\frac{7 (11 b B-3 A c) \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )}{32 \sqrt{2} \sqrt [4]{b} c^{15/4}}-\frac{7 (11 b B-3 A c) \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}+1\right )}{32 \sqrt{2} \sqrt [4]{b} c^{15/4}}-\frac{x^{11/2} (b B-A c)}{4 b c \left (b+c x^2\right )^2} \]
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Rubi [A] time = 0.246662, antiderivative size = 322, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 11, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.423, Rules used = {1584, 457, 288, 321, 329, 297, 1162, 617, 204, 1165, 628} \[ -\frac{x^{7/2} (11 b B-3 A c)}{16 b c^2 \left (b+c x^2\right )}+\frac{7 x^{3/2} (11 b B-3 A c)}{48 b c^3}-\frac{7 (11 b B-3 A c) \log \left (-\sqrt{2} \sqrt [4]{b} \sqrt [4]{c} \sqrt{x}+\sqrt{b}+\sqrt{c} x\right )}{64 \sqrt{2} \sqrt [4]{b} c^{15/4}}+\frac{7 (11 b B-3 A c) \log \left (\sqrt{2} \sqrt [4]{b} \sqrt [4]{c} \sqrt{x}+\sqrt{b}+\sqrt{c} x\right )}{64 \sqrt{2} \sqrt [4]{b} c^{15/4}}+\frac{7 (11 b B-3 A c) \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )}{32 \sqrt{2} \sqrt [4]{b} c^{15/4}}-\frac{7 (11 b B-3 A c) \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}+1\right )}{32 \sqrt{2} \sqrt [4]{b} c^{15/4}}-\frac{x^{11/2} (b B-A c)}{4 b c \left (b+c x^2\right )^2} \]
Antiderivative was successfully verified.
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Rule 1584
Rule 457
Rule 288
Rule 321
Rule 329
Rule 297
Rule 1162
Rule 617
Rule 204
Rule 1165
Rule 628
Rubi steps
\begin{align*} \int \frac{x^{21/2} \left (A+B x^2\right )}{\left (b x^2+c x^4\right )^3} \, dx &=\int \frac{x^{9/2} \left (A+B x^2\right )}{\left (b+c x^2\right )^3} \, dx\\ &=-\frac{(b B-A c) x^{11/2}}{4 b c \left (b+c x^2\right )^2}+\frac{\left (\frac{11 b B}{2}-\frac{3 A c}{2}\right ) \int \frac{x^{9/2}}{\left (b+c x^2\right )^2} \, dx}{4 b c}\\ &=-\frac{(b B-A c) x^{11/2}}{4 b c \left (b+c x^2\right )^2}-\frac{(11 b B-3 A c) x^{7/2}}{16 b c^2 \left (b+c x^2\right )}+\frac{(7 (11 b B-3 A c)) \int \frac{x^{5/2}}{b+c x^2} \, dx}{32 b c^2}\\ &=\frac{7 (11 b B-3 A c) x^{3/2}}{48 b c^3}-\frac{(b B-A c) x^{11/2}}{4 b c \left (b+c x^2\right )^2}-\frac{(11 b B-3 A c) x^{7/2}}{16 b c^2 \left (b+c x^2\right )}-\frac{(7 (11 b B-3 A c)) \int \frac{\sqrt{x}}{b+c x^2} \, dx}{32 c^3}\\ &=\frac{7 (11 b B-3 A c) x^{3/2}}{48 b c^3}-\frac{(b B-A c) x^{11/2}}{4 b c \left (b+c x^2\right )^2}-\frac{(11 b B-3 A c) x^{7/2}}{16 b c^2 \left (b+c x^2\right )}-\frac{(7 (11 b B-3 A c)) \operatorname{Subst}\left (\int \frac{x^2}{b+c x^4} \, dx,x,\sqrt{x}\right )}{16 c^3}\\ &=\frac{7 (11 b B-3 A c) x^{3/2}}{48 b c^3}-\frac{(b B-A c) x^{11/2}}{4 b c \left (b+c x^2\right )^2}-\frac{(11 b B-3 A c) x^{7/2}}{16 b c^2 \left (b+c x^2\right )}+\frac{(7 (11 b B-3 A c)) \operatorname{Subst}\left (\int \frac{\sqrt{b}-\sqrt{c} x^2}{b+c x^4} \, dx,x,\sqrt{x}\right )}{32 c^{7/2}}-\frac{(7 (11 b B-3 A c)) \operatorname{Subst}\left (\int \frac{\sqrt{b}+\sqrt{c} x^2}{b+c x^4} \, dx,x,\sqrt{x}\right )}{32 c^{7/2}}\\ &=\frac{7 (11 b B-3 A c) x^{3/2}}{48 b c^3}-\frac{(b B-A c) x^{11/2}}{4 b c \left (b+c x^2\right )^2}-\frac{(11 b B-3 A c) x^{7/2}}{16 b c^2 \left (b+c x^2\right )}-\frac{(7 (11 b B-3 A c)) \operatorname{Subst}\left (\int \frac{1}{\frac{\sqrt{b}}{\sqrt{c}}-\frac{\sqrt{2} \sqrt [4]{b} x}{\sqrt [4]{c}}+x^2} \, dx,x,\sqrt{x}\right )}{64 c^4}-\frac{(7 (11 b B-3 A c)) \operatorname{Subst}\left (\int \frac{1}{\frac{\sqrt{b}}{\sqrt{c}}+\frac{\sqrt{2} \sqrt [4]{b} x}{\sqrt [4]{c}}+x^2} \, dx,x,\sqrt{x}\right )}{64 c^4}-\frac{(7 (11 b B-3 A c)) \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt [4]{b}}{\sqrt [4]{c}}+2 x}{-\frac{\sqrt{b}}{\sqrt{c}}-\frac{\sqrt{2} \sqrt [4]{b} x}{\sqrt [4]{c}}-x^2} \, dx,x,\sqrt{x}\right )}{64 \sqrt{2} \sqrt [4]{b} c^{15/4}}-\frac{(7 (11 b B-3 A c)) \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt [4]{b}}{\sqrt [4]{c}}-2 x}{-\frac{\sqrt{b}}{\sqrt{c}}+\frac{\sqrt{2} \sqrt [4]{b} x}{\sqrt [4]{c}}-x^2} \, dx,x,\sqrt{x}\right )}{64 \sqrt{2} \sqrt [4]{b} c^{15/4}}\\ &=\frac{7 (11 b B-3 A c) x^{3/2}}{48 b c^3}-\frac{(b B-A c) x^{11/2}}{4 b c \left (b+c x^2\right )^2}-\frac{(11 b B-3 A c) x^{7/2}}{16 b c^2 \left (b+c x^2\right )}-\frac{7 (11 b B-3 A c) \log \left (\sqrt{b}-\sqrt{2} \sqrt [4]{b} \sqrt [4]{c} \sqrt{x}+\sqrt{c} x\right )}{64 \sqrt{2} \sqrt [4]{b} c^{15/4}}+\frac{7 (11 b B-3 A c) \log \left (\sqrt{b}+\sqrt{2} \sqrt [4]{b} \sqrt [4]{c} \sqrt{x}+\sqrt{c} x\right )}{64 \sqrt{2} \sqrt [4]{b} c^{15/4}}-\frac{(7 (11 b B-3 A c)) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\frac{\sqrt{2} \sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )}{32 \sqrt{2} \sqrt [4]{b} c^{15/4}}+\frac{(7 (11 b B-3 A c)) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\frac{\sqrt{2} \sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )}{32 \sqrt{2} \sqrt [4]{b} c^{15/4}}\\ &=\frac{7 (11 b B-3 A c) x^{3/2}}{48 b c^3}-\frac{(b B-A c) x^{11/2}}{4 b c \left (b+c x^2\right )^2}-\frac{(11 b B-3 A c) x^{7/2}}{16 b c^2 \left (b+c x^2\right )}+\frac{7 (11 b B-3 A c) \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )}{32 \sqrt{2} \sqrt [4]{b} c^{15/4}}-\frac{7 (11 b B-3 A c) \tan ^{-1}\left (1+\frac{\sqrt{2} \sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )}{32 \sqrt{2} \sqrt [4]{b} c^{15/4}}-\frac{7 (11 b B-3 A c) \log \left (\sqrt{b}-\sqrt{2} \sqrt [4]{b} \sqrt [4]{c} \sqrt{x}+\sqrt{c} x\right )}{64 \sqrt{2} \sqrt [4]{b} c^{15/4}}+\frac{7 (11 b B-3 A c) \log \left (\sqrt{b}+\sqrt{2} \sqrt [4]{b} \sqrt [4]{c} \sqrt{x}+\sqrt{c} x\right )}{64 \sqrt{2} \sqrt [4]{b} c^{15/4}}\\ \end{align*}
Mathematica [C] time = 0.316034, size = 176, normalized size = 0.55 \[ \frac{\frac{2 c^{3/4} x^{3/2} (3 b B-2 A c) \, _2F_1\left (\frac{3}{4},2;\frac{7}{4};-\frac{c x^2}{b}\right )}{b}+\frac{2 c^{3/4} x^{3/2} (A c-b B) \, _2F_1\left (\frac{3}{4},3;\frac{7}{4};-\frac{c x^2}{b}\right )}{b}+\frac{(3 A c-9 b B) \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{-b}}\right )}{\sqrt [4]{-b}}+\frac{(9 b B-3 A c) \tanh ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{-b}}\right )}{\sqrt [4]{-b}}+2 B c^{3/4} x^{3/2}}{3 c^{15/4}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.018, size = 357, normalized size = 1.1 \begin{align*}{\frac{2\,B}{3\,{c}^{3}}{x}^{{\frac{3}{2}}}}-{\frac{11\,A}{16\,c \left ( c{x}^{2}+b \right ) ^{2}}{x}^{{\frac{7}{2}}}}+{\frac{19\,Bb}{16\,{c}^{2} \left ( c{x}^{2}+b \right ) ^{2}}{x}^{{\frac{7}{2}}}}-{\frac{7\,Ab}{16\,{c}^{2} \left ( c{x}^{2}+b \right ) ^{2}}{x}^{{\frac{3}{2}}}}+{\frac{15\,B{b}^{2}}{16\,{c}^{3} \left ( c{x}^{2}+b \right ) ^{2}}{x}^{{\frac{3}{2}}}}+{\frac{21\,\sqrt{2}A}{128\,{c}^{3}}\ln \left ({ \left ( x-\sqrt [4]{{\frac{b}{c}}}\sqrt{x}\sqrt{2}+\sqrt{{\frac{b}{c}}} \right ) \left ( x+\sqrt [4]{{\frac{b}{c}}}\sqrt{x}\sqrt{2}+\sqrt{{\frac{b}{c}}} \right ) ^{-1}} \right ){\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}+{\frac{21\,\sqrt{2}A}{64\,{c}^{3}}\arctan \left ({\sqrt{2}\sqrt{x}{\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}+1 \right ){\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}+{\frac{21\,\sqrt{2}A}{64\,{c}^{3}}\arctan \left ({\sqrt{2}\sqrt{x}{\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}-1 \right ){\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}-{\frac{77\,\sqrt{2}Bb}{128\,{c}^{4}}\ln \left ({ \left ( x-\sqrt [4]{{\frac{b}{c}}}\sqrt{x}\sqrt{2}+\sqrt{{\frac{b}{c}}} \right ) \left ( x+\sqrt [4]{{\frac{b}{c}}}\sqrt{x}\sqrt{2}+\sqrt{{\frac{b}{c}}} \right ) ^{-1}} \right ){\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}-{\frac{77\,\sqrt{2}Bb}{64\,{c}^{4}}\arctan \left ({\sqrt{2}\sqrt{x}{\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}+1 \right ){\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}-{\frac{77\,\sqrt{2}Bb}{64\,{c}^{4}}\arctan \left ({\sqrt{2}\sqrt{x}{\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}-1 \right ){\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.81858, size = 2367, normalized size = 7.35 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.18073, size = 410, normalized size = 1.27 \begin{align*} \frac{2 \, B x^{\frac{3}{2}}}{3 \, c^{3}} + \frac{19 \, B b c x^{\frac{7}{2}} - 11 \, A c^{2} x^{\frac{7}{2}} + 15 \, B b^{2} x^{\frac{3}{2}} - 7 \, A b c x^{\frac{3}{2}}}{16 \,{\left (c x^{2} + b\right )}^{2} c^{3}} - \frac{7 \, \sqrt{2}{\left (11 \, \left (b c^{3}\right )^{\frac{3}{4}} B b - 3 \, \left (b c^{3}\right )^{\frac{3}{4}} A c\right )} \arctan \left (\frac{\sqrt{2}{\left (\sqrt{2} \left (\frac{b}{c}\right )^{\frac{1}{4}} + 2 \, \sqrt{x}\right )}}{2 \, \left (\frac{b}{c}\right )^{\frac{1}{4}}}\right )}{64 \, b c^{6}} - \frac{7 \, \sqrt{2}{\left (11 \, \left (b c^{3}\right )^{\frac{3}{4}} B b - 3 \, \left (b c^{3}\right )^{\frac{3}{4}} A c\right )} \arctan \left (-\frac{\sqrt{2}{\left (\sqrt{2} \left (\frac{b}{c}\right )^{\frac{1}{4}} - 2 \, \sqrt{x}\right )}}{2 \, \left (\frac{b}{c}\right )^{\frac{1}{4}}}\right )}{64 \, b c^{6}} + \frac{7 \, \sqrt{2}{\left (11 \, \left (b c^{3}\right )^{\frac{3}{4}} B b - 3 \, \left (b c^{3}\right )^{\frac{3}{4}} A c\right )} \log \left (\sqrt{2} \sqrt{x} \left (\frac{b}{c}\right )^{\frac{1}{4}} + x + \sqrt{\frac{b}{c}}\right )}{128 \, b c^{6}} - \frac{7 \, \sqrt{2}{\left (11 \, \left (b c^{3}\right )^{\frac{3}{4}} B b - 3 \, \left (b c^{3}\right )^{\frac{3}{4}} A c\right )} \log \left (-\sqrt{2} \sqrt{x} \left (\frac{b}{c}\right )^{\frac{1}{4}} + x + \sqrt{\frac{b}{c}}\right )}{128 \, b c^{6}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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